How to find the zero's of f(x)=1−x3?
2 Answers
Nov 15, 2016
Explanation:
Using the difference of cubes formula
=(1−x)(12+1⋅x+x2)
=(1−x)(x2+x+1)
Now, setting this equal to
The first equation gives us
The second equation has no real solutions. We can see this by observing that the discriminant
=−12±√−32
Thus the only solution to
Nov 15, 2016
I propose a different method.
Solve for
Get rid of the cube:
Hence,
Hopefully this helps!