How to find the zero's of #f(x)=1-x^3#?
2 Answers
Explanation:
Using the difference of cubes formula
#=(1-x)(1^2+1*x+x^2)#
#=(1-x)(x^2+x+1)#
Now, setting this equal to
The first equation gives us
The second equation has no real solutions. We can see this by observing that the discriminant
#=-1/2+-sqrt(-3)/2#
Thus the only solution to
I propose a different method.
Solve for
Get rid of the cube:
Hence,
Hopefully this helps!