How to find the zero's of f(x)=1-x^3?
2 Answers
Nov 15, 2016
Explanation:
Using the difference of cubes formula
=(1-x)(1^2+1*x+x^2)
=(1-x)(x^2+x+1)
Now, setting this equal to
The first equation gives us
The second equation has no real solutions. We can see this by observing that the discriminant
=-1/2+-sqrt(-3)/2
Thus the only solution to
Nov 15, 2016
I propose a different method.
Solve for
Get rid of the cube:
Hence,
Hopefully this helps!