Question

How to write standard form of equation through point (-6,-2) and Slope - 1/3?

Answer 1

For a point `(x_1,y_1) = (-6,-2)` and a slope of `m=- 1/3`

`(y-y_1)/(x-x_1) = m`

becomes
`(y+2)/(x+6) = -1/3`

`3y+6 = -x -6`

`3y = -x -12`

`y =-1/3x -4`