Question

Question below?

Answer 1

Please see below.

Explanation:

The problem is as shown below.

In this figure, as `BC` bisects `/_ABQ`, `m/_ABC=m/_CBQ=x`

Now according to alternate segment theorem (also known as the tangent-chord theorem) - in any circle, the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.

therefore `m/_CBQ=m/_BAC=x`

and in `DeltaABC`, `m/_BAC=m/_ABC=x`

as two angles of `DeltaABC` areequal, it is an isosceles trangle

and hence opposites are equal i.e. `AC=BC`.