Question

If `15/4 L` of a gas at room temperature exerts a pressure of `42 kPa` on its container, what pressure will the gas exert if the container's volume changes to `12/7 L`?

Answer 1

The new pressure is `=91.875kPa`

Explanation:

Apply Boyle's Law

`P_1V_1=P_2V_2`, at constant temperature

The initial pressure is `P_1=42kPa`

The initial volume is `V_1=15/4L`

The final volume is `V_2=12/7L`

The final pressure is

`P_2=V_1/V_2*P_1=(15/4)/(12/7)*42=91.875kPa`