Question

If `24 L` of a gas at room temperature exerts a pressure of `72 kPa` on its container, what pressure will the gas exert if the container's volume changes to `16 L`?

Answer 1

`P_2=108" " kPa`

Explanation:

`V_1=24" "L`
`P_1=72" "kPa`
`V_2=16" "L`
`P_2=?`

`"using Boyle's law";`

`P_1*V_1=P_2*V_2`

`72*24=P_2*16`

`P_2=(72*24)/16`

`P_2=108" " kPa`