If #4/3 L# of a gas at room temperature exerts a pressure of #35 kPa# on its container, what pressure will the gas exert if the container's volume changes to #7/4 L#?

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Answer 1 · 2017-02-23T14:52:39

The pressure is #=45.9kPa#

We apply Boyle's Law

#P_1V_1=P_2V_2#

#P_1=35kPa#

#V_1=4/3L#

#V_2=7/4L#

#P_2=V_1/V_2*P_1#

#=(7/4)/(4/3)*35#

#=7/4*3/4*35#

#=45.9kPa#