If 4^x= 7, then what does 4^ (-2x) equal? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer iceman · Becca M. · Don't Memorise Sep 1, 2015 If 4^x = 7 then 4^(-2x) = 1/49 Explanation: 4^x = 7 4^(-2x) = 1/4^(2x) = 1/[(4^x)^2] = 1/(7)^2 = 1/49 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 36221 views around the world You can reuse this answer Creative Commons License