Question

If `5/7 L` of a gas at room temperature exerts a pressure of `9 kPa` on its container, what pressure will the gas exert if the container's volume changes to `5/9 L`?

Answer 1

`P_2=11,57 " "kPa`

Explanation:

`"you should use the Boyle's law"`
`9*cancel(5)/7=P_2*cancel(5)/9`
`P_2=(9*9)/7`
`P_2=11,57 " "kPa`