If 538 mol of octane combusts, what volume of carbon dioxide is produced at 14.0°C and .995 atm?

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Answer 1 · 2016-05-08T08:47:01

Over one hundred thousands litres of carbon dioxide gas are evolved.

Balanced combustion equation:

#C_8H_18(l) + 17/2O_2(g) rarr 8CO_2(g) + 9H_2O(l)#

So, given that #538*mol# of octane combust, clearly, there are #8xx538*mol# #CO_2# evolved under complete combustion.

#V=(nRT)/P#

#=#

#(8xx538*cancel(mol)xx0.0821*L*cancel(atm)*cancel(K^-1)*cancel(mol^-1)xx287*cancelK)/(0.995*cancel(atm))#

#??*L#

What is the volume in #m^3#?