Question

If `8 L` of a gas at room temperature exerts a pressure of `42 kPa` on its container, what pressure will the gas exert if the container's volume changes to `9 L`?

Answer 1

The pressure should DECREASE slightly.

Explanation:

For a given quantity of gas at constant temperature, `P_1V_1=P_2V_2`. And thus the pressure should DECREASE is the volume INCREASES:

`P_2=(P_1V_1)/V_2=(42*"kPa"xx8*cancel"L")/(9*cancel"L")`

`=??"kPa"`?