If a current of $1 A$ $1 A$ passing through a circuit generates $9 W$ $9 W$ of power, what is the resistance of the circuit?

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Answer 1 · 2016-02-07T12:57:12

$9Omega$

We know that $P=IV$ .

We also know that by ohm's law $V=IR$ . We can put this $V$ into the equation for power to obtain:

$P=I^2R$

Now rearrange to get $R$ and we get:

$R = P/I^2$

Put your values of $I=1A$ and $P=9W$ into the equation and we get:

$R = 9/1^2=9Omega$

If a current of 1 A1A1 A passing through a circuit generates 9 W9W9 W of power, what is the resistance of the circuit?