If a current of 2 A2A passing through a circuit generates 15 W15W of power, what is the resistance of the circuit?

1 Answer
Jan 30, 2016

Assuming that the resistors are connected in series, the effective resistance is 3.75 Omega.

Explanation:

P = VI

Since by Ohm's Law, V=IR,
P = I^2R.

15W=(2"A")^2R_{"eff"}

R_{"eff"} = 15/4 Omega