If a current of $4 A$ $4 A$ passing through a circuit generates $16 W$ $16 W$ of power, what is the resistance of the circuit?

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Answer 1 · 2016-09-08T11:31:07

$V = I R$ $V=IR$ and $P = I V$ $P=IV$ , so $P = I^{2} R$ $P=I^2R$

$V = I R$ $V=IR$ and $P = I V$ $P=IV$ , so by substitution, $P = I^{2} R$ $P=I^2R$

In your example, $P = 16 W$ $P=16W$ and $I = 4 A$ $I=4A$

$16 = 4^{2} R$ $16=4^2R$

$R = \frac{16}{4^{2}}$ $R=16/4^2$

$R=1Omega$

If a current of 4 A4A4 A passing through a circuit generates 16 W16W16 W of power, what is the resistance of the circuit?