If a current of 8 A8A passing through a circuit generates 14 W14W of power, what is the resistance of the circuit?

1 Answer
Jan 13, 2016

The resistance in the circuit will be 0.22 Omega

Explanation:

I would combine two laws I have memorised here: Ohm's Law,

V = IR

and the Power Law

P = VI

I have a current, I, of "8 A" (ampere) and a power, P, of "14 W" (watt). I have been asked for a resistance, R Omega (ohm).

So I want a formula that includes only those three things. If I want to get rid of the V in the Power Law, I can replace it with what Ohm's Law says is equal to V= IR. So

P = (IR) * I = I^2 * R

I need to rearrange to make R the subject, so I divide both sides by I^2 and swap the sides:

R = P/(I^2) = 14/(8^2) = 14/64 = 0.22 color(white)(a)Omega (rounded to two decimal places).