If a current of $8 A$ $8 A$ passing through a circuit generates $32 W$ $32 W$ of power, what is the resistance of the circuit?

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Answer 1 · 2016-07-19T17:04:09

I found: $0.5Omega$

In general Power will be:
$P=V*I$
where $V$ is voltage and $I$ current.

Using Ohm's Law, $V=R*I$ , you can manipulate the above expression to introduce Resistance $R$ as:

$P=V*I=color(red)(R*I)*I=R*I^2$
in your case:
$32=8^2*R$
rearranging:
$R=0.5Omega$

If a current of 8 A8A8 A passing through a circuit generates 32 W32W32 W of power, what is the resistance of the circuit?