If a current of 8 A8A passing through a circuit generates 34 W34W of power, what is the resistance of the circuit?

1 Answer
Mar 4, 2016

The power is dependant on the voltage and the current.
p=UxxIp=U×I or: Watt=Volt x Ampere

Explanation:

p=UxxI->U=(p)/(I)p=U×IU=pI
Fill in what we know:
U=34/8=4.25VU=348=4.25V

For a this voltage to generate this current the resistance follows Ohm's law:
R=(U)/(I)R=UI or Ohm=Volt/Ampere
Or:
R=4.25/8=0.53125Omega~~0.53Omega