If a current of $8 A$ $8 A$ passing through a circuit generates $72 W$ $72 W$ of power, what is the resistance of the circuit?

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Answer 1 · 2018-03-14T22:07:40

$1.125Omega$

$P = I^2R$

power = current^2 * resistance

this can be rearranged to give

$R = P/(I^2)$

resistance = power / (current^2)

here, current $= 8A$

$8^2$ = $64$

power $= 72W$

$P/(I^2) = 72/64$

$R = 72/64Omega$

$= 9/8Omega$

$= 1.125Omega$

If a current of 8 A8A8 A passing through a circuit generates 72 W72W72 W of power, what is the resistance of the circuit?