If a current of $8 A$ $8 A$ passing through a circuit generates $96 W$ $96 W$ of power, what is the resistance of the circuit?

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Answer 1 · 2018-03-13T17:44:50

$1.5 Ω$ $"1.5 Ω"$

Power ( $P$ $P$ ) and resistance ( $R$ $R$ ) are related as

$P = i^{2} R$ $P = i^2R$

$R = \frac{P}{i^{2}} = \frac{96 Watt}{{(8 A)}^{2}} = 1.5 Ω$ $R = P/(i^2) = "96 Watt"/("8 A")^2 = "1.5 Ω"$

If a current of 8A8 A passing through a circuit generates 96W96 W of power, what is the resistance of the circuit?