If a projectile is shot at an angle of $\frac{2 π}{3}$ $(2pi)/3$ and at a velocity of $16 \frac{m}{s}$ $16 m/s$ , when will it reach its maximum height?

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If a projectile is shot at an angle of $\frac{2 π}{3}$ $(2pi)/3$ and at a velocity of $16 \frac{m}{s}$ $16 m/s$ , when will it reach its maximum height?

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Answer 1 · 2016-04-16T09:46:21

Time to reach at maximum height $t = \frac{u sin α}{g} = \frac{16 \times sin (2 \frac{π}{3})}{10} s = 1.39 s$ $t = (usinalpha)/g=(16xxsin(2pi/3))/10s=1.39s$

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If a projectile is shot at an angle of $\frac{2 π}{3}$ $(2pi)/3$ and at a velocity of $16 \frac{m}{s}$ $16 m/s$ , when will it reach its maximum height?

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If a projectile is shot at an angle of $\frac{2 π}{3}$ $(2pi)/3$ and at a velocity of $16 \frac{m}{s}$ $16 m/s$ , when will it reach its maximum height?