If a projectile is shot at an angle of (2pi)/3 and at a velocity of 26 m/s, when will it reach its maximum height?

1 Answer
Apr 4, 2016

t_m=2,29 " s"

Explanation:

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"given data:"
"initial velocity :"v_i=26 m/s
"angle :"alpha=(2pi)/3
sin(2pi)/3=0,866
"elapsed time to reach its maximum height :"t_m=(v_i*sin alpha)/g
g=9,81 m/s^2

t_m=(26*0,866)/(9,81)

t_m=2,29 " s"