If a projectile is shot at an angle of $(3pi)/8$ and at a velocity of $12 m/s$ , when will it reach its maximum height?

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Answer 1 · 2017-07-23T15:12:25

$t=1.1secs$

Maximum height is reached when the vertical component of velocity $=0$

the initial vertical component $" u=12sin((3pi)/8)$

we will use

$v=u + g t uarr$

$=12sin((3pi)/8)-10t$

$t=12/10sin((3pi)/8)$

$t=1.1secs$

If a projectile is shot at an angle of (3pi)/8(3pi)/8 and at a velocity of 12 m/s12 m/s, when will it reach its maximum height?