Question

If a projectile is shot at an angle of `(3pi)/8` and at a velocity of `21 m/s`, when will it reach its maximum height?

Answer 1

The projectile will move upwards because of its vertical component of velocity i.e `21 sin ((3pi)/8)`

Let,the projectile will reach it's maximum height in time `t`,so we can write, `0=21 sin((3pi)/8) -g t` (using, `v=u-g t` and at the highest point of motion velocity becomes zero)

So, `t=1.98 s`