If a projectile is shot at an angle of $\frac{3 π}{8}$ $(3pi)/8$ and at a velocity of $8 \frac{m}{s}$ $8 m/s$ , when will it reach its maximum height?

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If a projectile is shot at an angle of $\frac{3 π}{8}$ $(3pi)/8$ and at a velocity of $8 \frac{m}{s}$ $8 m/s$ , when will it reach its maximum height?

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Answer 1 · 2016-03-06T11:30:08

$t ≅ 0, 41 s$ $t~=0,41 s$

Explanation:

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$t = v_{i} \cdot \frac{sin α}{g}$ $t=v_i*sin alpha/g$
$α = 3 \frac{π}{18} \cdot \frac{180}{π} = 30^{o} sin 30 = 0, 5$ $alpha=3pi/18*180/pi=30^o" "sin 30=0,5$
$t = \frac{8 \cdot 0, 5}{9, 81}$ $t=(8*0,5)/(9,81)$

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If a projectile is shot at an angle of $\frac{3 π}{8}$ $(3pi)/8$ and at a velocity of $8 \frac{m}{s}$ $8 m/s$ , when will it reach its maximum height?

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If a projectile is shot at an angle of $\frac{3 π}{8}$ $(3pi)/8$ and at a velocity of $8 \frac{m}{s}$ $8 m/s$ , when will it reach its maximum height?