Question

If a projectile is shot at an angle of `(5pi)/12` and at a velocity of `1 1 m/s`, when will it reach its maximum height?

Answer 1

When a projectile reaches the maxima of its parabolic trajectory, `nu_y = 0`.

Given,

`nu_y = 0`

`nu_(y0) = nusintheta approx (10.6"m")/"s"`

`a = g`

Now, recall,

`nu = nu_0 + at`

Hence, it will take,

`=> t = (Deltanu_y)/a approx 1.08"s"`

for the projectile to reach its maximum height.