Question

If a projectile is shot at an angle of `(5pi)/12` and at a velocity of `1 m/s`, when will it reach its maximum height??

Answer 1

`t~=0,098 s`

Explanation:

`t_m=(v_i*sin alpha)/g`
`v_i:" initial velocity"`
`alpha: "projectile angle"`
`alpha=(5pi)/12*180/pi`
`alpha=75^o`
`t=(1*sin 75^o)/(9,81)`
`t=(1*0,966)/(9,81)`
`t~=0,098 s`