If a projectile is shot at an angle of $\frac{5 π}{12}$ $(5pi)/12$ and at a velocity of $1 \frac{m}{s}$ $1 m/s$ , when will it reach its maximum height??

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If a projectile is shot at an angle of $\frac{5 π}{12}$ $(5pi)/12$ and at a velocity of $1 \frac{m}{s}$ $1 m/s$ , when will it reach its maximum height??

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Answer 1 · 2016-02-11T19:34:32

$t ≅ 0, 098 s$ $t~=0,098 s$

Explanation:

$t_{m} = \frac{v_{i} \cdot sin α}{g}$ $t_m=(v_i*sin alpha)/g$
$v_{i} : initial velocity$ $v_i:" initial velocity"$
$α : projectile angle$ $alpha: "projectile angle"$
$α = \frac{5 π}{12} \cdot \frac{180}{π}$ $alpha=(5pi)/12*180/pi$
$α = 75^{o}$ $alpha=75^o$
$t = \frac{1 \cdot {sin 75}^{o}}{9, 81}$ $t=(1*sin 75^o)/(9,81)$
$t = \frac{1 \cdot 0, 966}{9, 81}$ $t=(1*0,966)/(9,81)$
$t ≅ 0, 098 s$ $t~=0,098 s$

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If a projectile is shot at an angle of $\frac{5 π}{12}$ $(5pi)/12$ and at a velocity of $1 \frac{m}{s}$ $1 m/s$ , when will it reach its maximum height??

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Explanation:

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If a projectile is shot at an angle of $\frac{5 π}{12}$ $(5pi)/12$ and at a velocity of $1 \frac{m}{s}$ $1 m/s$ , when will it reach its maximum height??