If a projectile is shot at an angle of $(5pi)/12$ and at a velocity of $16 m/s$ , when will it reach its maximum height??

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Answer 1 · 2017-10-12T22:27:55

1.545 seconds

$T = (u sin θ) / g$

$T = (16 ms^-1 sin ((5 π)/12)) / (10 ms^-2)$

$T = (16 × 0.9659) / (10)$ s

$T = 1.545$ $text(seconds)$

If a projectile is shot at an angle of (5pi)/12(5pi)/12 and at a velocity of 16 m/s16 m/s, when will it reach its maximum height??