If a projectile is shot at an angle of $\frac{π}{12}$ $pi/12$ and at a velocity of $1 \frac{m}{s}$ $1 m/s$ , when will it reach its maximum height??

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Answer 1 · 2016-12-02T07:19:29

The maximum height is $= 0.013 m$ $=0.013m$

The maximum height is given by

$h_(max)=(v_0^2sin^2theta)/(2g)$

$v_0=1ms^(-1)$

$theta=pi/12$

$g=10ms^(-2)$

So,

$h_(max)=1*sin^2(pi/12)/(2*10)$

$=0.013m$

If a projectile is shot at an angle of pi/12π12pi/12 and at a velocity of 1 m/s1ms1 m/s, when will it reach its maximum height??