If a projectile is shot at an angle of $\frac{π}{12}$ $pi/12$ and at a velocity of $22 \frac{m}{s}$ $22 m/s$ , when will it reach its maximum height??

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If a projectile is shot at an angle of $\frac{π}{12}$ $pi/12$ and at a velocity of $22 \frac{m}{s}$ $22 m/s$ , when will it reach its maximum height??

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Answer 1 · 2018-01-31T15:20:26

$0.57 s$ $0.57 s$

Explanation:

here,the projectile will go up due to the vertical component of its velocity, i.e $22 sin (\frac{π}{12})$ $22 sin (pi/12)$ or, $5.7 \frac{m}{s}$ $5.7 m/s$

So,it will reach the highest point,when its upward velocity becomes zero,

so,we can apply $v = u - g t$ $v=u-g t$

So,for $v = 0$ $v=0$ , $t = \frac{5.7}{10} s$ $t= 5.7/10 s$ or, $0.57 s$ $0.57 s$

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If a projectile is shot at an angle of $\frac{π}{12}$ $pi/12$ and at a velocity of $22 \frac{m}{s}$ $22 m/s$ , when will it reach its maximum height??

1 Answer

Explanation:

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If a projectile is shot at an angle of $\frac{π}{12}$ $pi/12$ and at a velocity of $22 \frac{m}{s}$ $22 m/s$ , when will it reach its maximum height??