Question

If a projectile is shot at an angle of `pi/2` and at a velocity of `34 m/s`, when will it reach its maximum height??

Answer 1

The upward motion of the projectile will be due to its vertical component of velocity,now initially during the projection,its vertical component of velocity was `34 sin (pi/2) =34ms^-1`

So,if it reaches its maximum height at time `t` at that instant its upward component of velocity will be zero,

so,we can use, `v=u-g t`

so, here we can write,

`0=34 -g t`

so, `t=3.47 s`

Well look carefully here the projectile was thrown directly upwards,i.e it had no horizontal displacement,as its horizontal component of velocity was `34 cos (pi/2) =0`