If a projectile is shot at an angle of $pi/3$ and at a velocity of $26 m/s$ , when will it reach its maximum height??

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Answer 1 · 2016-12-28T16:08:44

$t=2.3$ seconds rounded to 1 decimal place

The maximum height is when the vertical velocity component of the projectile is equal to the vertically downward velocity due to gravity.

Tony B

Thus we have the model:

$=> Rsin(theta)="g"t$

Where
$R= 26m/s$
$theta=pi/3$
$g~~9.81 m/s^2 larr" known"$

$t$ is time in seconds

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

This becomes:

$=>26color(red)(m/s)sin(pi/3)=9.81color(red)(m/s^2)color(white)(.)t$

You manipulate the units in the same way you do the numbers

$=>t= 26/9.81 sin(pi/3)color(red)( xx(cancel(m))/(cancel(s))xxs^(cancel(color(white)(.)2))/(cancel(m)) larr" dealing with the units")$

$t=2.29527...$ seconds

$t=2.3$ seconds rounded to 1 decimal place

If a projectile is shot at an angle of pi/3pi/3 and at a velocity of 26 m/s26 m/s, when will it reach its maximum height??