If a projectile is shot at an angle of $pi/3$ and at a velocity of $29 m/s$ , when will it reach its maximum height??

Question

1455 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-02T11:21:34

$t=2,56 " "s$

$alpha=pi/3" sin (pi/3)=0,866$
$"initial velocity :"v_i=29 " "m/s$

$"it has "v_y=0"; if object reaches its maximum height."$

$v_y=v_i*sin alpha-g*t$

$0=v_i*sin alpha-g*t$

$t=(v_i*sin alpha)/g" elapsed time to the maximum height"$

$t=(29*0,866)/(9,81)$

$t=2,56 " "s$

If a projectile is shot at an angle of pi/3pi/3 and at a velocity of 29 m/s29 m/s, when will it reach its maximum height??