If a projectile is shot at an angle of $\frac{π}{4}$ $pi/4$ and at a velocity of $2 \frac{m}{s}$ $2 m/s$ , when will it reach its maximum height??

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Answer 1 · 2016-01-26T07:30:03

height = 20 cm

since $k e$ $ke$ = $\frac{1}{2} m v^{2}$ $1/2mv^2$
$K . E = \frac{1}{2} m 2^{2}$ $K.E=1/2m2^2$
$k . e = 2 m J$ $k.e=2m J$

but K.e =workdone=potential energy of the body at maximum height

therefore $2 m = m g h$ $2m=mgh$

2=10h

$h = \frac{1}{5} m$ $h=1/5m$
or $h = 20 c m$ $h=20cm$

If a projectile is shot at an angle of π4pi/4 and at a velocity of 2ms2 m/s, when will it reach its maximum height??