If a projectile is shot at an angle of $\frac{π}{4}$ $pi/4$ and at a velocity of $32 \frac{m}{s}$ $32 m/s$ , when will it reach its maximum height??

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Answer 1 · 2018-03-02T10:58:03

$2.31 s$ $2.31s$

here,the upward movement of the projectile will be due to the upward component of its velocity i.e $32 sin (\frac{π}{4})$ $32 sin (pi/4)$

So,we can apply, $v = u - g t$ $v=u-g t$ to find the time taken to reach its maximum height.

At,maximum height upward component of velocity is zero,initial upward velocity is $32 sin (\frac{π}{4})$ $32 sin (pi/4)$

So, $t = \frac{32 sin (\frac{π}{4})}{g} = 2.31 s$ $t= (32 sin (pi/4))/g=2.31 s$

If a projectile is shot at an angle of pi/4π4pi/4 and at a velocity of 32 m/s32ms32 m/s, when will it reach its maximum height??