If a projectile is shot at an angle of $pi/4$ and at a velocity of $4 m/s$ , when will it reach its maximum height??

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Answer 1 · 2018-04-27T05:41:19

The time is $=0.29s$

Resolving in the vertical direction $uarr^+$

The initial velocity is $u_0=(4)sin(1/4pi)ms^-1$

The time to reach the greatest height is $=ts$

Applying the equation of motion

$v=u+at=u- g t$

The time is $t=(v-u)/(-g)=(0-(4)sin(1/4pi))/(-9.8)=0.29s$

If a projectile is shot at an angle of pi/4pi/4 and at a velocity of 4 m/s4 m/s, when will it reach its maximum height??