If a projectile is shot at an angle of $\frac{π}{8}$ $(pi)/8$ and at a velocity of $13 \frac{m}{s}$ $13 m/s$ , when will it reach its maximum height?

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Answer 1 · 2016-10-12T12:17:30

$t = \frac{24.70}{19.62} = 1.26 s$ $t=(24.70)/(19.62)=1.26 " "s$

$t = \frac{v_{i}^{2} \cdot {sin}^{2} α}{2 \cdot g} = \frac{{(v_{y})}_{y}^{2}}{2 g}$ $t=(v_i^2*sin^2 alpha)/(2*g)=(v_y)^2/(2g)$

$v_{y} = v_{i} \cdot sin α = 13 \cdot sin (\frac{π}{8}) = 4.97$ $v_y=v_i*sin alpha=13*sin (pi/8)=4.97$

$t = \frac{{(4.97)}^{2}}{2 \cdot 9.81}$ $t=(4.97)^2/(2*9.81)$

$t = \frac{24.70}{19.62} = 1.26 s$ $t=(24.70)/(19.62)=1.26 " "s$

If a projectile is shot at an angle of π8(pi)/8 and at a velocity of 13ms13 m/s, when will it reach its maximum height?