If a projectile is shot at an angle of $(pi)/8$ and at a velocity of $7 m/s$ , when will it reach its maximum height?

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Answer 1 · 2017-04-17T11:15:42

The time is $=0.27s$

Resolving in the vertical direction $uarr^+$

initial velocity is $u_y=vsintheta=7*sin(1/8pi)$

At the maximum height, $v=0$

We apply the equation of motion

$v=u+at$

to calculate the time to reach the greatest height

$0=7sin(1/8pi)-g*t$

$t=7/g*sin(1/8pi)$

$=0.27s$

If a projectile is shot at an angle of (pi)/8(pi)/8 and at a velocity of 7 m/s7 m/s, when will it reach its maximum height?