If a projectile is shot vertically from the ground at 1 m/s1ms, how long will it remain in the air?

1 Answer
Apr 29, 2016

~~0.2s0.2s

Explanation:

Since the projectile is projected vertically then free vertical motion under gravity to be applied.
Here Initial velocity u = 1m/su=1ms
If its time of flight be taken as T s, then after Ts it will return to the initial position at the ground ,making a verticalb displacement h=0h=0 Taking acceleration due to gravity g =9.8ms^-2g=9.8ms2
we can write:
h=uxxT-1/2xxgxxT^2=>0=1xxT-1/2xx9.8xxT^2h=u×T12×g×T20=1×T12×9.8×T2
:. T=1/4.9s~~0.2s