If an object is dropped, how fast will it be moving after 16s?

1 Answer
1s2s2p
Apr 11, 2018

Theoretical:
v=u+at, where:

  • v = final velocity (ms−1)
  • u =initial velocity (ms−1)
  • a = acceleration (ms−2)
  • t = time (s)

We will take a=9.81ms−2

v=0+16(9.81)=156.96ms−1≈157ms−1

Realistic:
The speed will depend on the shape of the object and surface area (large drag force or small drag force), height it is dropped from (to allow for a 16s fall), environment (different mediums will have different drag forces for the same object), how high the object is (higher up you go, the smaller the drag force but the smaller the acceleration due to gravity).

Related questions
See all questions in Falling Objects
Impact of this question
1673 views around the world
You can reuse this answer
Creative Commons License