Question

If an object is dropped, how fast will it be moving after `23 s`?

Answer 1

`"225.4 m/s"`

Explanation:

Use equation of motion

`"v = u + at"`

where

• `"u ="` Velocity at `"t = 0"`
• `"v ="` Velocity after time `"t"`
• `"a ="` Acceleration
• `"t ="` Time at which velocity is `"v"`

`"v = 0 m/s + (9.8 m/s"^2 × "23 s) = 225.4 m/s"`