If an object with uniform acceleration (or deceleration) has a speed of #12 m/s# at #t=0# and moves a total of 8 m by #t=1#, what was the object's rate of acceleration?
1 Answer
Explanation:
We're asked to find te magnitude of the acceleration of an object with some given kinemtics quantities.
We know:
-
initial velocity
#v_(0x)# is#12# #"m/s"# -
change in position
#Deltax# is#8# #"m"# -
time
#t# is#1# #"s"#
We can use the equation
Plugging in known values, and solving for the acceleration
The acceleration is in the negative direction, which means the object will keep slowing down in the positive direction until it eventually slows to a stop, and it then speeds up in the negative direction.