Question

If an object with uniform acceleration (or deceleration) has a speed of `3 m/s` at `t=0` and moves a total of 58 m by `t=6`, what was the object's rate of acceleration?

Answer 1

a=20/9 m/s^2
a=-20/9 m/s^2

Explanation:

`"area under graph is equal displacement of 58 m"`
`58=(3+k)/2*6"; "58=(3+k)*3"; "58=9+3*k`
`49=3*k"; "k=49/3`
`"rate of acceleration is equal tangent of graph"`
`a=(3-k)/6" or " a=(k-3)/a`
`a=(3-49/3)/6" ; " a=-20/9 m/s^2`
`a=(49/3-3)/6" ; " a=20/9 m/s^2`