Question

If an object with uniform acceleration (or deceleration) has a speed of `4 m/s` at `t=0` and moves a total of 8 m by `t=4`, what was the object's rate of acceleration?

Answer 1

I found a deceleration of `-1.0m/s^2`

Explanation:

We can try to use:
`x_f-x_i=v_it+1/2at^2`
with:
`x_f-x_i=8m`
`t=4s` (I think)
`v_i=4m/s`
to get:
`8=4*4+1/2a(4)^2`
`8=16+8a`
`a=-8/8=-1.0m/s^2`