Question

If an object with uniform acceleration (or deceleration) has a speed of `9 m/s` at `t=0` and moves a total of 44 m by `t=3`, what was the object's rate of acceleration?

Answer 1

`3.dot7ms^-2`

Explanation:

Given distance moved `s=44m` in time `3s`, initial speed at `t=0` is `9ms^-1`. To find acceleration `a`.
We can use kinematic equation connecting above variables
`s=ut+1/2at^2`
Plugin given values
`44=9xx3+1/2a(3)^2`
`=>9/2a=44-27`
`=>9/2a=44-27`
`=>a=3.dot7ms^-2`