If dice are rolled what is probability that a six first appears on the 10th roll?

1 Answer
Oct 5, 2017

P("first 6 appears on 10th roll")=(5^9)/(6^10)=0.0323011166

Explanation:

P("first 6 appears on 10th roll")

color(white)("XXX")=color(green)(P("6 did not appear on first 9 rolls"))xxcolor(blue)(P("6 appears on 10th roll"))

P("6 did not appear on a single roll")=5/6

color(green)(P("6 did not appear on 9 rolls in succession"))= color(green)((5/6)^9)

color(blue)(P("6 did appear on 10th roll"))=color(blue)(1/6)

:. P("first 6 appears on 10th roll")=color(green)((5^9)/(6^9))xxcolor(blue)(1/6)

color(white)("XXXXXXXXXXXXXXXXXXX")=(5^9)/(6^10)

(use calculator to evaluate beyond this point if desired)