Question

If `f(x)= 1-x^3` and `g(x)= 1/x` how do you find f(g(x))?

Answer 1

`f(g(x)) = 1- (1/x)^3`

Explanation:

`f(g(x))` basically means that `g(x)` is being taken as an "input" for `f` instead of the usual "input" `x`.

So, to compute `f(g(x))`, you need to plug `g(x)` for every occurance of `x` in `f(x)`:

`f(g(x)) = f(1/x) = 1- (1/x)^3`