Question

If `h(x)=f(x)g(x)` and `f(x)=2x+5`, how do you determine g(x) given `h(x)=-2x^2-5x`?

Answer 1

`g(x) = -x`

Explanation:

`h(x) = f(x)*g(x)`

`g(x) =( h(x))/f(x)`

`g(x) = (-2x^2 - 5x)/(2x+5)`

`g(x) = (-xcancel((2x + 5)))/cancel(2x+5)`

`g(x) = -x`