If sides A and B of a triangle have lengths of 1 and 2 respectively, and the angle between them is $\frac{5 π}{8}$ $(5pi)/8$ , then what is the area of the triangle?

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If sides A and B of a triangle have lengths of 1 and 2 respectively, and the angle between them is $\frac{5 π}{8}$ $(5pi)/8$ , then what is the area of the triangle?

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Answer 1 · 2018-05-03T07:43:39

A = 0.924 $u n i t s^{2}$ $units^2$

Explanation:

Remember that the equation for finding the area of a triangle is
1/2 ab sinC
So in this case the area is equal to: 1/2x1x2xsin(5 $π$ $pi$ /8)
Which simply becomes sin(5 $π$ $pi$ /8) (remember to have your calculator in radians mode)

Answer 2 · 2018-05-03T11:27:11

$A_{t} = 0.9239 sq units$ $color(crimson)(A_t = 0.9239 " sq units"$

Explanation:

Formula for area of triangle = (1/2) b c sin A, knowing two sides and the included angle.

$b = 1, c = 2, ˆ A = \frac{5 π}{8}$ $b = 1, c = 2, hat A = (5pi)/8$

$"Area of Triangle " A_t = cancel(1/2) * 1 * cancel2 * sin ((5pi)/8)$

$color(crimson)(A_t = sin ((5pi)/8) = 0.9239 " sq units"$

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If sides A and B of a triangle have lengths of 1 and 2 respectively, and the angle between them is $\frac{5 π}{8}$ $(5pi)/8$ , then what is the area of the triangle?

2 Answers

Explanation:

Explanation:

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If sides A and B of a triangle have lengths of 1 and 2 respectively, and the angle between them is $\frac{5 π}{8}$ $(5pi)/8$ , then what is the area of the triangle?