If sides A and B of a triangle have lengths of 2 and 1 respectively, and the angle between them is $\frac{11 π}{12}$ $(11pi)/12$ , then what is the area of the triangle?

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Answer 1 · 2016-03-13T09:12:00

$0.2588$ $0.2588$

Given two sides $b$ $b$ and $c$ $c$ and included angle $A$ $A$ between them,

area of a triangle is given by $\frac{1}{2} \times b \times c \times sin A$ $1/2xxbxxcxxsinA$

Hence area of triangle would be $\frac{1}{2} \times 2 \times 1 \times sin (\frac{11 π}{12})$ $1/2xx2xx1xxsin((11pi)/12)$

or $sin (\frac{11 π}{12}) = 0.2588$ $sin((11pi)/12)=0.2588$

If sides A and B of a triangle have lengths of 2 and 1 respectively, and the angle between them is 11π12(11pi)/12, then what is the area of the triangle?