If sides A and B of a triangle have lengths of 2 and 9 respectively, and the angle between them is (5pi)/65π6, then what is the area of the triangle?

1 Answer
Aug 27, 2016

4.5 square units.

Explanation:

Given a triangle, where 2 sides and the angle between them are known, as in this question. Then we can calculate the area (A) of the triangle using.

color(orange)"Reminder"Reminder

color(red)(|bar(ul(color(white)(a/a)color(black)(A=1/2xxaxxbxxsin("angle between them"))color(white)(a/a)|)))
where a and b are the 2 known sides.

here a = 2 , b = 9 and angle between them =(5pi)/6

rArrA=1/2xx2xx9xxsin((5pi)/6)

color(orange)"Reminder"

color(red)(|bar(ul(color(white)(a/a)color(black)(sin((5pi)/6)=sin(pi-(5pi)/6)=sin(pi/6)=1/2)color(white)(a/a)|)))

rArrA=1/2xx2xx9xxsin(pi/6)

rArrA=1/2xx2xx9xx1/2=4.5" square units"