If sides A and B of a triangle have lengths of 3 and 7 respectively, and the angle between them is $\frac{2 π}{3}$ $(2pi)/3$ , then what is the area of the triangle?

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Answer 1 · 2015-12-13T19:27:34

$9, 093$ $9,093$ square units

We may use the area rule :

Area triangle $A B C = \frac{1}{2} a b sin C$ $ABC=1/2ab sinC$

$= \frac{1}{2} \times 3 \times 7 \times sin (\frac{2 π}{3})$ $=1/2xx3xx7xxsin((2pi)/3)$

$= 9, 093$ $=9,093$ square units

If sides A and B of a triangle have lengths of 3 and 7 respectively, and the angle between them is 2π3(2pi)/3, then what is the area of the triangle?